What is the limit as x approaches 0 of 3/(1+e^{1/x)} ?

The limit as x approaches 0 of 3/(1+e^{1/x)} is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0 of 3/(1+e^{1/x)}

x \to 0 lim (\frac{3}{1 + e ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{3}{1 + e ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{3}{1 + e ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{3}{1 + e ^{\frac{1}{x}}}) = 3

= diverges

\int \frac{x ^{2}}{9 - x ^{2}} d x

f (t) = 1 + t

y^{^{'}} + 3 x^{2} y = x^{2}

f (x) = x^{4} - 13 x^{2} + 36, at x = - 1

\frac{d}{d x} (x^{\frac{1}{2}} \cdot (x^{2} + x - 4))

What is the limit as x approaches 0 of 3/(1+e^{1/x)} ?
The limit as x approaches 0 of 3/(1+e^{1/x)} is diverges