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Popular >

y^'+a*y-b=0

Solution

y^{^{'}} + a \cdot y - b = 0

Solution

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

Solution steps

y^{'} (t) + a \cdot y - b = 0

Solve separable ODE:

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

y = - \frac{e ^{- a t - c_{1} a}}{a} + \frac{b}{a}

Popular Examples

normal of y=9xe^x,(0,0)normal of

y = 9 x e^{x}, (0, 0)

area y= 1/2 x,y= 6/x ,y=2x area

y = \frac{1}{2} x, y = \frac{6}{x}, y = 2 x

limit as x approaches 5-of 3/(x-5)

x \to 5 - lim (\frac{3}{x - 5})

limit as x approaches 2-of x-1

x \to 2 - lim (x - 1)

derivative of-4*sec^2(4x)derivative of

- 4 \cdot sec^{2} (4 x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+a*y-b=0 ?
The solution for y^'+a*y-b=0 is y=-(e^{-at-c_{1}a})/a+b/a