What is the d/(dz)(sin^2(z)) ?

The d/(dz)(sin^2(z)) is sin(2z)

What is the first d/(dz)(sin^2(z)) ?

The first d/(dz)(sin^2(z)) is sin(2z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d z} (sin^{2} (z))

sin (2 z)

Solution steps

\frac{d}{d z} (sin^{2} (z))

Apply the chain rule:

2 sin (z) \frac{d}{d z} (sin (z))

= 2 sin (z) \frac{d}{d z} (sin (z))

\frac{d}{d z} (sin (z)) = cos (z)

= 2 sin (z) cos (z)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= sin (2 z)

\frac{2}{s ^{2} + s - 2}

\frac{( s + 1 )}{s ^{2} + 2 s + 5}

\int \frac{6 t - 15}{3 t ^{2} - 2} d t

\int \frac{60 ln ( 3 ^{3^{x + 1}} )}{3 ^{x} - 1} d x