What is the integral from 0 to 4 of (1/4 x+(x+1)) ?

The integral from 0 to 4 of (1/4 x+(x+1)) is 14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of (1/4 x+(x+1))

\int_{0}^{4} (\frac{1}{4} x + (x + 1)) d x

14

Solution steps

\int_{0}^{4} \frac{1}{4} x + x + 1 d x

Add similar elements:

\frac{1}{4} x + x = \frac{5}{4} x

= \int_{0}^{4} \frac{5}{4} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} \frac{5}{4} x d x + \int_{0}^{4} 1 d x

\int_{0}^{4} \frac{5}{4} x d x = 10

\int_{0}^{4} 1 d x = 4

= 10 + 4

Simplify

= 14

\frac{d}{d x} (e^{- \frac{a}{x}})

x \to 3 lim (\frac{4 x - 12}{x - 3})

\int \frac{sin ( x )}{x} d x

\int \frac{x ^{2} + 2}{x} d x

\int tan^{3} (7 π x) d x

What is the integral from 0 to 4 of (1/4 x+(x+1)) ?
The integral from 0 to 4 of (1/4 x+(x+1)) is 14