What is the first derivative of 8+3x^2 ?

The first derivative of 8+3x^2 is 6x

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derivative of 8+3x^2

\frac{d}{d x} (8 + 3 x^{2})

6 x

Solution steps

\frac{d}{d x} (8 + 3 x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8) + \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (8) = 0

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 + 6 x

Simplify

= 6 x

\int ln (9 x + 4) d x

\frac{d}{d x} (\frac{1 - 2 x}{4 + x})

n = 0 \sum \infty 4 (\frac{2}{3})^{2 n}

\int x^{- \frac{7}{4}} d x

f (x) = \frac{x}{2 ( x ^{2} + 7 ) ^{\frac{3}{4}}}