What is the derivative of f(x)=(x+1)/x ?

The derivative of f(x)=(x+1)/x is -1/(x^2)

What is the first derivative of f(x)=(x+1)/x ?

The first derivative of f(x)=(x+1)/x is -1/(x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

f (x) = \frac{x + 1}{x}

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x + 1}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x + 1 ) x - \frac{d x}{d x} ( x + 1 )}{x ^{2}}

\frac{d}{d x} (x + 1) = 1

\frac{d x}{d x} = 1

= \frac{1 \cdot x - 1 \cdot ( x + 1 )}{x ^{2}}

Simplify

\frac{1 \cdot x - 1 \cdot ( x + 1 )}{x ^{2}} : - \frac{1}{x ^{2}}

= - \frac{1}{x ^{2}}

\frac{d}{d x} (\frac{1}{1 + cos ( x )})

f (x) = e^{9}

w \to a lim (\frac{a ^{2} - w ^{2}}{a - w})

\int e^{1 - 5 x} d x

What is the derivative of f(x)=(x+1)/x ?
The derivative of f(x)=(x+1)/x is -1/(x^2)
What is the first derivative of f(x)=(x+1)/x ?
The first derivative of f(x)=(x+1)/x is -1/(x^2)