What is the integral of sqrt(4x^2+1)x ?

The integral of sqrt(4x^2+1)x is 1/12 (4x^2+1)^{3/2}+C

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integral of sqrt(4x^2+1)x

\int 4 x^{2} + 1 x d x

\frac{1}{12} (4 x^{2} + 1)^{\frac{3}{2}} + C

Solution steps

\int 4 x^{2} + 1 x d x

Apply u-substitution

: \int \frac{u}{8} d u

= \int \frac{u}{8} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{8} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = 4 x^{2} + 1

= \frac{1}{8} \cdot \frac{2}{3} (4 x^{2} + 1)^{\frac{3}{2}}

Simplify

\frac{1}{8} \cdot \frac{2}{3} (4 x^{2} + 1)^{\frac{3}{2}} : \frac{1}{12} (4 x^{2} + 1)^{\frac{3}{2}}

= \frac{1}{12} (4 x^{2} + 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{12} (4 x^{2} + 1)^{\frac{3}{2}} + C

x^{3} - x

\int π^{x} d x

(9 - t)^{\frac{1}{2}}

\int_{0}^{1} (e^{x} - x e^{x}) d x

f (x) = \frac{ln ( x )}{13 + x}

What is the integral of sqrt(4x^2+1)x ?
The integral of sqrt(4x^2+1)x is 1/12 (4x^2+1)^{3/2}+C