What is the integral of (10x^4-2sec^2(x)) ?

The integral of (10x^4-2sec^2(x)) is 2x^5-2tan(x)+C

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integral of (10x^4-2sec^2(x))

\int (10 x^{4} - 2 sec^{2} (x)) d x

2 x^{5} - 2 tan (x) + C

Solution steps

\int 10 x^{4} - 2 sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 10 x^{4} d x - \int 2 sec^{2} (x) d x

\int 10 x^{4} d x = 2 x^{5}

\int 2 sec^{2} (x) d x = 2 tan (x)

= 2 x^{5} - 2 tan (x)

Add a constant to the solution

= 2 x^{5} - 2 tan (x) + C

(1 + x)^{- 2}

n \to \infty lim (\frac{2 n ^{5} - 3 n ^{4} + 8}{3 n ^{5} + 1})

f (x) = 3 x - 4

\int_{1}^{2} 6 e^{6 x} d x

(2 x)^{6 x}

What is the integral of (10x^4-2sec^2(x)) ?
The integral of (10x^4-2sec^2(x)) is 2x^5-2tan(x)+C