What is the sum from n=1 to infinity of (-5)^{-n} ?

The sum from n=1 to infinity of (-5)^{-n} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of (-5)^{-n}

n = 1 \sum \infty (- 5)^{- n}

converges

Solution steps

n = 1 \sum \infty (- 5)^{- n}

Apply Series Ratio Test:

converges

= converges

\frac{d}{d x} (sin^{2} (x) + 2^{s i n (x)})

n = 1 \sum \infty \frac{n}{n ^{2} + 1}

\frac{d}{d x} (x^{\frac{1}{3}} y^{\frac{2}{3}})

\frac{d}{d x} (\frac{1}{2} x^{2} - x + \frac{1}{6} x^{3})

\int x^{2} \cdot x d x

What is the sum from n=1 to infinity of (-5)^{-n} ?
The sum from n=1 to infinity of (-5)^{-n} is converges