What is the tangent of f(x)=-3x^3-2x,(-1,5) ?

The tangent of f(x)=-3x^3-2x,(-1,5) is y=-11x-6

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tangent of f(x)=-3x^3-2x,(-1,5)

tangent of

f (x) = - 3 x^{3} - 2 x, (- 1, 5)

y = - 11 x - 6

Solution steps

Find the slope of

f (x) = - 3 x^{3} - 2 x : \frac{df ( x )}{d x} = - 9 x^{2} - 2

Compute the slope of

f (x) = - 3 x^{3} - 2 x

(- 1, 5) : m = - 11

Find the line with slope m=

- 11

and passing through

(- 1, 5) : y = - 11 x - 6

y = - 11 x - 6

x^{2} y^{^{'}} + y = 0

n lo g_{10} (n)

\int \frac{1}{( x - 1 ) ^{\frac{2}{3}}} d x

\int 9 x^{2} sin (8 x) d x

\frac{\partial}{\partial y} (tan (x) + y)

What is the tangent of f(x)=-3x^3-2x,(-1,5) ?
The tangent of f(x)=-3x^3-2x,(-1,5) is y=-11x-6