What is the derivative of 8sqrt(3x^2+9) ?

The derivative of 8sqrt(3x^2+9) is (24x)/(sqrt(3x^2+9))

What is the first derivative of 8sqrt(3x^2+9) ?

The first derivative of 8sqrt(3x^2+9) is (24x)/(sqrt(3x^2+9))

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derivative of

8 3 x^{2} + 9

\frac{24 x}{3 x ^{2} + 9}

Solution steps

\frac{d}{d x} (8 3 x^{2} + 9)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (3 x^{2} + 9)

Apply the chain rule:

\frac{1}{2 3 x ^{2} + 9} \frac{d}{d x} (3 x^{2} + 9)

= \frac{1}{2 3 x ^{2} + 9} \frac{d}{d x} (3 x^{2} + 9)

\frac{d}{d x} (3 x^{2} + 9) = 6 x

= 8 \cdot \frac{1}{2 3 x ^{2} + 9} \cdot 6 x

Simplify

8 \cdot \frac{1}{2 3 x ^{2} + 9} \cdot 6 x : \frac{24 x}{3 x ^{2} + 9}

= \frac{24 x}{3 x ^{2} + 9}

\frac{\partial}{\partial x} (42 e^{7 x} y)

f (x) = \frac{x}{x ^{2} + 64}

\int_{0}^{1} 2 π (2 - y) (4 - 4 y^{2}) d y

y = - 2 x + 3, (0, 1)

\int x^{2} cos (a) x d x

What is the derivative of 8sqrt(3x^2+9) ?
The derivative of 8sqrt(3x^2+9) is (24x)/(sqrt(3x^2+9))
What is the first derivative of 8sqrt(3x^2+9) ?
The first derivative of 8sqrt(3x^2+9) is (24x)/(sqrt(3x^2+9))