What is the integral from 0 to 2 of 6^x ?

The integral from 0 to 2 of 6^x is (35)/(ln(6))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 6^x

\int_{0}^{2} 6^{x} d x

\frac{35}{ln ( 6 )}

Decimal Notation

19.53387 \dots

Solution steps

\int_{0}^{2} 6^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{6 ^{x}}{ln ( 6 )}]_{0}^{2}

Compute the boundaries:

\frac{35}{ln ( 6 )}

= \frac{35}{ln ( 6 )}

x \to 0 lim (\frac{9}{x} - \frac{9}{x ^{2} + x})

x \to 1 lim (\frac{2 x - 2}{x - 1})

\int_{1}^{2} (x x - 1) d x

\int_{0}^{5} 1 + x d x

\frac{d}{d x} ((ln (x)) d x)

What is the integral from 0 to 2 of 6^x ?
The integral from 0 to 2 of 6^x is (35)/(ln(6))