What is the limit as x approaches 9 of 6/((x-9)^2) ?

The limit as x approaches 9 of 6/((x-9)^2) is infinity

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limit as x approaches 9 of 6/((x-9)^2)

x \to 9 lim (\frac{6}{( x - 9 ) ^{2}})

\infty

Solution steps

x \to 9 lim (\frac{6}{( x - 9 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 9 - lim (\frac{6}{( x - 9 ) ^{2}}) = \infty

x \to 9 + lim (\frac{6}{( x - 9 ) ^{2}}) = \infty

= \infty

x \to 0 lim (\frac{x}{x + x ^{2}})

x \to 0 lim (3 x - 2)

\int x x + 5 d x

x \to 0 lim (\frac{tanh ( x )}{x})

\frac{d}{d x} (\frac{1}{3} tan (x))

What is the limit as x approaches 9 of 6/((x-9)^2) ?
The limit as x approaches 9 of 6/((x-9)^2) is infinity