What is the derivative of y= 4/(x^4) ?

The derivative of y= 4/(x^4) is -(16)/(x^5)

What is the first derivative of y= 4/(x^4) ?

The first derivative of y= 4/(x^4) is -(16)/(x^5)

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derivative of

y = \frac{4}{x ^{4}}

- \frac{16}{x ^{5}}

Solution steps

\frac{d}{d x} (\frac{4}{x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- 4 x^{- 4 - 1})

Simplify

4 (- 4 x^{- 4 - 1}) : - \frac{16}{x ^{5}}

= - \frac{16}{x ^{5}}

(x + 2)^{^{'}}

f (x) = (2 x^{3} + 3 x) (x - 3) (x + 5)

y^{^{''}} - 8 y^{^{'}} + 20 y = 100 x^{2} - 26 x e^{x}

\int - x + 2 d x

\frac{d}{d x} (16 ln (x))

What is the derivative of y= 4/(x^4) ?
The derivative of y= 4/(x^4) is -(16)/(x^5)
What is the first derivative of y= 4/(x^4) ?
The first derivative of y= 4/(x^4) is -(16)/(x^5)