What is the first derivative of sin(kt) ?

The first derivative of sin(kt) is 0

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derivative of sin(kt)

\frac{d}{d x} (sin (k t))

0

Solution steps

\frac{d}{d x} (sin (k t))

Treat

k, t

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

f (x) = (5 + 2 x) e^{- 3 x}

\frac{d}{d x} (2 \cdot e^{2 x})

\int_{3}^{4} \frac{1}{sin ( x )} d x

5 cos (2 t) - 3 sin (3 t)

y^{^{''}} - \frac{6}{x} y^{^{'}} + \frac{10}{x ^{2}} y = 0