What is the derivative of 7/(4x+1) ?

The derivative of 7/(4x+1) is -(28)/((4x+1)^2)

What is the first derivative of 7/(4x+1) ?

The first derivative of 7/(4x+1) is -(28)/((4x+1)^2)

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\frac{d}{d x} (\frac{7}{4 x + 1})

- \frac{28}{( 4 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{7}{4 x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (\frac{1}{4 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 7 \frac{d}{d x} ((4 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

= - \frac{1}{( 4 x + 1 ) ^{2}} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= 7 (- \frac{1}{( 4 x + 1 ) ^{2}} \cdot 4)

Simplify

7 (- \frac{1}{( 4 x + 1 ) ^{2}} \cdot 4) : - \frac{28}{( 4 x + 1 ) ^{2}}

= - \frac{28}{( 4 x + 1 ) ^{2}}

y = e^{3 - x}

y + (x^{2} + y^{2}) d x - x d y = 0

6 x^{2} + (x^{3} + 2) \frac{d}{d x} y = 0

\frac{d}{d x} (\frac{12}{x})

\int (3 - x) (x) d x

What is the derivative of 7/(4x+1) ?
The derivative of 7/(4x+1) is -(28)/((4x+1)^2)
What is the first derivative of 7/(4x+1) ?
The first derivative of 7/(4x+1) is -(28)/((4x+1)^2)