What is the (sec^2(x))^' ?

The (sec^2(x))^' is 2sec^2(x)tan(x)

What is the first (sec^2(x))^' ?

The first (sec^2(x))^' is 2sec^2(x)tan(x)

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(sec^{2} (x))^{^{'}}

2 sec^{2} (x) tan (x)

Solution steps

(sec^{2} (x))^{'}

Apply the chain rule:

2 sec (x) (sec (x))^{'}

= 2 sec (x) (sec (x))^{'}

(sec (x))^{'} = sec (x) tan (x)

= 2 sec (x) sec (x) tan (x)

Simplify

2 sec (x) sec (x) tan (x) : 2 sec^{2} (x) tan (x)

= 2 sec^{2} (x) tan (x)

\int (- 4 x^{3}) d x

x \to 0 + lim (tan^{x} (9 x))

\frac{d}{d x} (π^{c o s (x)})

x \to 0 lim ((\frac{x + 2}{x})^{2} - 4)

2^{20}