What is (\partial)/(\partial x)(x+y^{1/2}) ?

The answer to (\partial)/(\partial x)(x+y^{1/2}) is 1

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(\partial)/(\partial x)(x+y^{1/2})

\frac{\partial}{\partial x} (x + y^{\frac{1}{2}})

1

Solution steps

\frac{\partial}{\partial x} (x + y^{\frac{1}{2}})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y^{\frac{1}{2}})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y^{\frac{1}{2}}) = 0

= 1 + 0

Simplify

= 1

x \to 0 lim (tan (7 x))

y^{^{'}} = y^{2} e^{2 x}

ln (\frac{2 + x}{1 + x})

\frac{d y}{d t} = t + t^{2}

\frac{d}{d x} (- \frac{x}{1 + x ^{2}})

What is (\partial)/(\partial x)(x+y^{1/2}) ?
The answer to (\partial)/(\partial x)(x+y^{1/2}) is 1