What is the limit as x approaches 0 of ((4e^x-4))/x ?

The limit as x approaches 0 of ((4e^x-4))/x is 4

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limit as x approaches 0 of ((4e^x-4))/x

x \to 0 lim (\frac{( 4 e ^{x} - 4 )}{x})

4

Solution steps

x \to 0 lim (\frac{4 e ^{x} - 4}{x})

Apply L'Hopital's Rule

: x \to 0 lim (\frac{4 e ^{x}}{1})

= x \to 0 lim (\frac{4 e ^{x}}{1})

Plug in the value

x = 0

= \frac{4 e ^{0}}{1}

Simplify

= 4

\frac{d}{d x} (sin (2 x^{2} \cdot e^{- x}))

f (x) = (x - 2) (2 x + 3), at x = 0

\int (x - 5) \cdot sin (x) d x

\int \frac{sin ( x ) tan ( x )}{9 + sec ^{2} ( x )} d x

t^{2} y^{^{''}} + 21 t y^{^{'}} + 100 y = 0

What is the limit as x approaches 0 of ((4e^x-4))/x ?
The limit as x approaches 0 of ((4e^x-4))/x is 4