What is the derivative of (8x+7)^2 ?

The derivative of (8x+7)^2 is 16(8x+7)

What is the first derivative of (8x+7)^2 ?

The first derivative of (8x+7)^2 is 16(8x+7)

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derivative of

(8 x + 7)^{2}

16 (8 x + 7)

Solution steps

\frac{d}{d x} ((8 x + 7)^{2})

Apply the chain rule:

2 (8 x + 7) \frac{d}{d x} (8 x + 7)

= 2 (8 x + 7) \frac{d}{d x} (8 x + 7)

\frac{d}{d x} (8 x + 7) = 8

= 2 (8 x + 7) \cdot 8

Simplify

= 16 (8 x + 7)

n = 1 \sum \infty \frac{ln ( n )}{8 n}

\int x^{2} x^{3} + 8 d x

\frac{d}{d x} (\frac{300}{3 + 17 e ^{- 0.0625 x}})

\frac{d}{d x} (x^{3} - 12 x^{2} + 45 x + 9)

x \to 2 lim (\frac{7}{x - 2})

What is the derivative of (8x+7)^2 ?
The derivative of (8x+7)^2 is 16(8x+7)
What is the first derivative of (8x+7)^2 ?
The first derivative of (8x+7)^2 is 16(8x+7)