What is area f(x)=x^2+x-56,g(x)=-x^2+3x+4 ?

The answer to area f(x)=x^2+x-56,g(x)=-x^2+3x+4 is 1331/3

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area f(x)=x^2+x-56,g(x)=-x^2+3x+4

area

f (x) = x^{2} + x - 56, g (x) = - x^{2} + 3 x + 4

\frac{1331}{3}

Decimal Notation

443.66666 \dots

Solution steps

Apply the area formula:

\int_{- 5}^{6} x^{2} + x - 56 - (- x^{2} + 3 x + 4) d x

Solve

\int_{- 5}^{6} x^{2} + x - 56 - (- x^{2} + 3 x + 4) d x : \frac{1331}{3}

The area is:

= \frac{1331}{3}

1 + \frac{a}{r} - \frac{b}{r ^{3}}

x^{2} y^{^{''}} - 3 x y^{^{'}} + 4 y = x + x^{2} ln (x)

\int \frac{sec ( x ) tan ( x )}{sec ( x ) - 1} d x

(x + 2) (2 x^{2} - 3)

\int x e^{k x} d x

What is area f(x)=x^2+x-56,g(x)=-x^2+3x+4 ?
The answer to area f(x)=x^2+x-56,g(x)=-x^2+3x+4 is 1331/3