What is the derivative of 9x+1-x^2 ?

The derivative of 9x+1-x^2 is -2x+9

What is the first derivative of 9x+1-x^2 ?

The first derivative of 9x+1-x^2 is -2x+9

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derivative of

9 x + 1 - x^{2}

- 2 x + 9

Solution steps

\frac{d}{d x} (9 x + 1 - x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 x) + \frac{d}{d x} (1) - \frac{d}{d x} (x^{2})

\frac{d}{d x} (9 x) = 9

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{2}) = 2 x

= 9 + 0 - 2 x

Simplify

= - 2 x + 9

x \to 1 lim (\frac{x ^{2} - 3 x}{x - 1})

y = (x^{2} + 4 x - 3)^{4}

\int \frac{e ^{2 y}}{e ^{y} - 1} d y

\frac{d y}{d x} - x y^{2} = 2 x y

\int t cos^{5} (t^{2}) d t

What is the derivative of 9x+1-x^2 ?
The derivative of 9x+1-x^2 is -2x+9
What is the first derivative of 9x+1-x^2 ?
The first derivative of 9x+1-x^2 is -2x+9