What is the derivative of tan(5x^2-x) ?

The derivative of tan(5x^2-x) is sec^2(5x^2-x)(10x-1)

What is the first derivative of tan(5x^2-x) ?

The first derivative of tan(5x^2-x) is sec^2(5x^2-x)(10x-1)

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\frac{d}{d x} (tan (5 x^{2} - x))

sec^{2} (5 x^{2} - x) (10 x - 1)

Solution steps

\frac{d}{d x} (tan (5 x^{2} - x))

Apply the chain rule:

sec^{2} (5 x^{2} - x) \frac{d}{d x} (5 x^{2} - x)

= sec^{2} (5 x^{2} - x) \frac{d}{d x} (5 x^{2} - x)

\frac{d}{d x} (5 x^{2} - x) = 10 x - 1

= sec^{2} (5 x^{2} - x) (10 x - 1)

\int 10 csc^{2} (5 x) cot (5 x) d x

\frac{\partial}{\partial x} (\frac{sin ( x + y )}{y ^{2}})

4 \frac{d y}{d x} - 12 x^{2} = 0

y = \frac{80}{x ^{6}}

y = 3 x + 2 cos (x)

What is the derivative of tan(5x^2-x) ?
The derivative of tan(5x^2-x) is sec^2(5x^2-x)(10x-1)
What is the first derivative of tan(5x^2-x) ?
The first derivative of tan(5x^2-x) is sec^2(5x^2-x)(10x-1)