What is (\partial)/(\partial x)((x-y)^n) ?

The answer to (\partial)/(\partial x)((x-y)^n) is n(x-y)^{n-1}

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(\partial)/(\partial x)((x-y)^n)

\frac{\partial}{\partial x} ((x - y)^{n})

n (x - y)^{n - 1}

Solution steps

\frac{\partial}{\partial x} ((x - y)^{n})

Treat

n, y

as a constant

Apply the chain rule:

n (x - y)^{n - 1} \frac{\partial}{\partial x} (x - y)

= n (x - y)^{n - 1} \frac{\partial}{\partial x} (x - y)

\frac{\partial}{\partial x} (x - y) = 1

= n (x - y)^{n - 1} \cdot 1

Simplify

= n (x - y)^{n - 1}

\int_{0}^{1} x^{2} arctan (x) d x

n = 1 \sum \infty \frac{10}{3 ^{n}}

\frac{d}{d x} (sec^{2} (x))

\int_{0}^{1} \frac{1}{( x + 1 ) ( x - 2 )} d x

\int \frac{x ^{2} - a ^{2}}{x} d x

What is (\partial)/(\partial x)((x-y)^n) ?
The answer to (\partial)/(\partial x)((x-y)^n) is n(x-y)^{n-1}