What is the derivative of-3sin(x-pi+x) ?

The derivative of-3sin(x-pi+x) is 3cos(x)+1

What is the first derivative of-3sin(x-pi+x) ?

The first derivative of-3sin(x-pi+x) is 3cos(x)+1

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\frac{d}{d x} (- 3 sin (x - π) + x)

3 cos (x) + 1

Solution steps

\frac{d}{d x} (- 3 sin (x - π) + x)

Simplify

- 3 sin (x - π) + x : 3 sin (x) + x

= \frac{d}{d x} (3 sin (x) + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 sin (x)) + \frac{d x}{d x}

\frac{d}{d x} (3 sin (x)) = 3 cos (x)

\frac{d x}{d x} = 1

= 3 cos (x) + 1

y^{^{'}} - 9 y = 27

\frac{d}{d x} (\frac{1}{5} x)

\int (\frac{x}{x ^{2} + y ^{2}} + \frac{1}{x} + \frac{1}{y}) d x

\frac{d}{d x} (\frac{3 + 5 x - 8 x}{x})

f (x) = cos (a^{3} + x^{3})

What is the derivative of-3sin(x-pi+x) ?
The derivative of-3sin(x-pi+x) is 3cos(x)+1
What is the first derivative of-3sin(x-pi+x) ?
The first derivative of-3sin(x-pi+x) is 3cos(x)+1