What is the derivative of (x+y^2) ?

The derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))

What is the first derivative of (x+y^2) ?

The first derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))

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\frac{d}{d x} ((x + y)^{2})

2 (x + y) (1 + \frac{d y}{d x})

Solution steps

\frac{d}{d x} ((x + y)^{2})

Apply the chain rule:

2 (x + y) \frac{d}{d x} (x + y)

= 2 (x + y) \frac{d}{d x} (x + y)

\frac{d}{d x} (x + y) = 1 + \frac{d y}{d x}

= 2 (x + y) (1 + \frac{d y}{d x})

\int cos (\frac{x}{5}) d x

\int x^{2} + 2 d x

h^{2} (2 t)

y = 3 x^{2} (x - 3)^{3}

\frac{d y}{y ( A - y )} = \frac{k}{A} d x

What is the derivative of (x+y^2) ?
The derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))
What is the first derivative of (x+y^2) ?
The first derivative of (x+y^2) is 2(x+y)(1+(dy)/(dx))