What is the solution for (dy)/(dx)+4x^2y=-10x^2 ?

The solution for (dy)/(dx)+4x^2y=-10x^2 is y=(e^{(-4x^3+c_{1})/3})/(2)-5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)+4x^2y=-10x^2

\frac{d y}{d x} + 4 x^{2} y = - 10 x^{2}

y = \frac{e ^{\frac{- 4 x ^{3} + c _{1}}{3}}}{2} - \frac{5}{2}

Solution steps

\frac{d y}{d x} + 4 x^{2} y = - 10 x^{2}

Solve separable ODE:

y = \frac{e ^{\frac{- 4 x ^{3} + c _{1}}{3}}}{2} - \frac{5}{2}

y = \frac{e ^{\frac{- 4 x ^{3} + c _{1}}{3}}}{2} - \frac{5}{2}

\frac{d}{d x} (\frac{( x ^{4} + 2 )}{ln ( x )})

x \to 6 lim (\frac{x}{x - 6})

\int (3 x + 2) cos (5 x) d x

y = x (x + 2) (x - 2), [- 2, 1]

\int_{1}^{4} - 6 t ln (t) d t

What is the solution for (dy)/(dx)+4x^2y=-10x^2 ?
The solution for (dy)/(dx)+4x^2y=-10x^2 is y=(e^{(-4x^3+c_{1})/3})/(2)-5/2