What is the solution for y^'=(x^2-y^2)/(xy),y(2)=5 ?

The solution for y^'=(x^2-y^2)/(xy),y(2)=5 is y=(sqrt(x^4+184))/(sqrt(2)x)

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y^'=(x^2-y^2)/(xy),y(2)=5

y^{^{'}} = \frac{x ^{2} - y ^{2}}{x y}, y (2) = 5

y = \frac{x ^{4} + 184}{2 x}

Solution steps

y^{'} (x) = \frac{x ^{2} - y ^{2}}{x y}

Solve Bernoulli ODE:

y = \frac{x ^{4} + 184}{2 x}

y = \frac{x ^{4} + 184}{2 x}

\frac{\partial}{\partial y} (e^{x y z^{4}} y z^{4})

\frac{\partial}{\partial y} (x^{2} - 2 x y + 2 y^{2})

f (x) = x^{3} - 4 x, (2, 0)

cos (x) - \frac{2}{2} x

x \to 1^{- 1} lim (- 1.6 x - 0.6)

What is the solution for y^'=(x^2-y^2)/(xy),y(2)=5 ?
The solution for y^'=(x^2-y^2)/(xy),y(2)=5 is y=(sqrt(x^4+184))/(sqrt(2)x)