What is the limit as x approaches 3+of x/(x^2-4x+3) ?

The limit as x approaches 3+of x/(x^2-4x+3) is infinity

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limit as x approaches 3+of x/(x^2-4x+3)

x \to 3 + lim (\frac{x}{x ^{2} - 4 x + 3})

\infty

Solution steps

x \to 3 + lim (\frac{x}{x ^{2} - 4 x + 3})

\frac{x}{x ^{2} - 4 x + 3} = x \frac{1}{x ^{2} - 4 x + 3}

= x \to 3 + lim (x \frac{1}{x ^{2} - 4 x + 3})

x \to a lim [f (x) \cdot g (x)] = x \to a lim f (x) \cdot x \to a lim g (x)

With the exception of indeterminate form

= x \to 3 + lim (x) \cdot x \to 3 + lim (\frac{1}{x ^{2} - 4 x + 3})

x \to 3 + lim (x) = 3

x \to 3 + lim (\frac{1}{x ^{2} - 4 x + 3}) = \infty

= 3 \cdot \infty

Apply Infinity Property:

c \cdot \infty = \infty

= \infty

x \to - 1 lim (3 x^{2} + 3 x^{3} + 10)

\frac{5}{2} sin (\frac{π x}{3}), \frac{5}{3} x, [0, 1.5]

y = 2 x, y = x^{2}

\int (x^{2} + 1)^{- 2} d x

y = x^{2} - 9, y = - x + 5, x = 0, x = 2

What is the limit as x approaches 3+of x/(x^2-4x+3) ?
The limit as x approaches 3+of x/(x^2-4x+3) is infinity