What is the derivative of 4x^2+4x^3 ?

The derivative of 4x^2+4x^3 is 8x+12x^2

What is the first derivative of 4x^2+4x^3 ?

The first derivative of 4x^2+4x^3 is 8x+12x^2

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\frac{d}{d x} (4 x^{2} + 4 x^{3})

8 x + 12 x^{2}

Solution steps

\frac{d}{d x} (4 x^{2} + 4 x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (4 x^{3})

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

= 8 x + 12 x^{2}

\int e^{- x} cos (7 x) d x

\frac{d}{d x} (ln (1 + 6 x))

(e^{- y} + 1) sin (x) d x = (1 + cos (x)) d y, y (0) = 0

\int p (p + 1)^{5} d p

\frac{\partial}{\partial y} (y - \frac{1}{x ^{2}})

What is the derivative of 4x^2+4x^3 ?
The derivative of 4x^2+4x^3 is 8x+12x^2
What is the first derivative of 4x^2+4x^3 ?
The first derivative of 4x^2+4x^3 is 8x+12x^2