What is the derivative of ln(x/4 (x-4)) ?

The derivative of ln(x/4 (x-4)) is (x-4)/x+ln(x/4)

What is the first derivative of ln(x/4 (x-4)) ?

The first derivative of ln(x/4 (x-4)) is (x-4)/x+ln(x/4)

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\frac{d}{d x} (ln (\frac{x}{4}) (x - 4))

\frac{x - 4}{x} + ln (\frac{x}{4})

Solution steps

\frac{d}{d x} (ln (\frac{x}{4}) (x - 4))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = ln (\frac{x}{4}), g = x - 4

= \frac{d}{d x} (ln (\frac{x}{4})) (x - 4) + \frac{d}{d x} (x - 4) ln (\frac{x}{4})

\frac{d}{d x} (ln (\frac{x}{4})) = \frac{1}{x}

\frac{d}{d x} (x - 4) = 1

= \frac{1}{x} (x - 4) + 1 \cdot ln (\frac{x}{4})

Simplify

\frac{1}{x} (x - 4) + 1 \cdot ln (\frac{x}{4}) : \frac{x - 4}{x} + ln (\frac{x}{4})

= \frac{x - 4}{x} + ln (\frac{x}{4})

\int \frac{sin ( x )}{cot ( x )} d x

\frac{s}{s ^{2} - 16}

y^{^{'}} = x^{2} - y - 2, y (0) = 1

\int \frac{x ^{2}}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\frac{d}{d x} (ln (7 x^{3}))

What is the derivative of ln(x/4 (x-4)) ?
The derivative of ln(x/4 (x-4)) is (x-4)/x+ln(x/4)
What is the first derivative of ln(x/4 (x-4)) ?
The first derivative of ln(x/4 (x-4)) is (x-4)/x+ln(x/4)