What is the integral of sin(2-3x) ?

The integral of sin(2-3x) is 1/3 cos(2-3x)+C

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integral of sin(2-3x)

\int sin (2 - 3 x) d x

\frac{1}{3} cos (2 - 3 x) + C

Solution steps

\int sin (2 - 3 x) d x

Apply u-substitution

: \int - \frac{1}{3} sin (u) d u

= \int - \frac{1}{3} sin (u) d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{3} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= - \frac{1}{3} (- cos (u))

Substitute back

u = 2 - 3 x

= - \frac{1}{3} (- cos (2 - 3 x))

Simplify

= \frac{1}{3} cos (2 - 3 x)

Add a constant to the solution

= \frac{1}{3} cos (2 - 3 x) + C

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\frac{d ^{2}}{d x ^{2}} (sec^{2} (x))

\frac{d}{d x} ((tan (x))^{t a n (x)})

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\int \frac{1}{x ^{2} + 49} d x

What is the integral of sin(2-3x) ?
The integral of sin(2-3x) is 1/3 cos(2-3x)+C