What is the tangent of f(x)=x^2-1,(5,24) ?

The tangent of f(x)=x^2-1,(5,24) is y=10x-26

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tangent of f(x)=x^2-1,(5,24)

tangent of

f (x) = x^{2} - 1, (5, 24)

y = 10 x - 26

Solution steps

Find the slope of

f (x) = x^{2} - 1 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} - 1

(5, 24) : m = 10

Find the line with slope m=

10

and passing through

(5, 24) : y = 10 x - 26

y = 10 x - 26

\int_{0}^{\frac{π}{2}} (cos^{2} (x)) d x

2 x^{2} + 8 x + 9

x \to 2 + lim (\frac{x - 1}{x - 2})

\int_{1}^{t} 15 x^{- 3} d x

\frac{d}{d x} (2 e^{3 x} + 1)

What is the tangent of f(x)=x^2-1,(5,24) ?
The tangent of f(x)=x^2-1,(5,24) is y=10x-26