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Popular >

y^'-y=te^{3t}

Solution

y^{^{'}} - y = t e^{3 t}

Solution

y = \frac{e ^{3 t} ( 2 t - 1 )}{4} + c_{1} e^{t}

Solution steps

y^{'} (t) - y = t e^{3 t}

Solve linear ODE:

y = \frac{e ^{3 t} ( 2 t - 1 )}{4} + c_{1} e^{t}

y = \frac{e ^{3 t} ( 2 t - 1 )}{4} + c_{1} e^{t}

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\frac{d}{d x} (4 - 5 x)

derivative of D(2x^2e^x)derivative of

D (2 x^{2} e^{x})

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=te^{3t} ?
The solution for y^'-y=te^{3t} is y=(e^{3t}(2t-1))/4+c_{1}e^t