What is the tangent of y=35x-16x^2,\at x=1 ?

The tangent of y=35x-16x^2,\at x=1 is y=3x+16

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tangent of y=35x-16x^2,\at x=1

tangent of

y = 35 x - 16 x^{2}, at x = 1

y = 3 x + 16

Solution steps

Find the tangent point:

(1, 19)

Find the slope of

y = 35 x - 16 x^{2} : \frac{d y}{d x} = 35 - 32 x

Compute the slope of

y = 35 x - 16 x^{2}

x = 1 : m = 3

Find the line with slope m=

3

and passing through

(1, 19) : y = 3 x + 16

y = 3 x + 16

h \to 1 lim (\frac{∣ h - 2 ∣ - 2}{h})

8 + 5 x + 7 x e^{x}

\frac{d}{d x} (x sin (9 x))

\frac{d}{d x} (tan (π \frac{x}{3}))

\int \frac{5}{x ( 1 + 5 x ) ^{2}} d x

What is the tangent of y=35x-16x^2,\at x=1 ?
The tangent of y=35x-16x^2,\at x=1 is y=3x+16