What is the solution for y^{''}+2y=sin((7t)/5) ?

The solution for y^{''}+2y=sin((7t)/5) is y=c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t)+25sin((7t)/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y=sin((7t)/5)

y^{^{''}} + 2 y = sin (\frac{7 t}{5})

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 25 sin (\frac{7 t}{5})

Solution steps

y^{''} (t) + 2 y = sin (\frac{7 t}{5})

Solve linear ODE:

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 25 sin (\frac{7 t}{5})

y = c_{1} cos (2 t) + c_{2} sin (2 t) + 25 sin (\frac{7 t}{5})

\int \frac{5}{244} x^{4} d x

\int cos^{2} (x) sin (x) d x

\int \frac{x ^{2}}{( x - 3 ) ( x + 2 ) ^{2}} d x

\frac{\partial}{\partial x} (x^{3} - 2 y^{2} - 2 y^{4} + 3 x^{2} y)

x \to \infty lim (\frac{e ^{1 - l n (x)}}{e ^{1 - l n (x) 2}})

What is the solution for y^{''}+2y=sin((7t)/5) ?
The solution for y^{''}+2y=sin((7t)/5) is y=c_{1}cos(sqrt(2)t)+c_{2}sin(sqrt(2)t)+25sin((7t)/5)