What is laplacetransform 1+t ?

The answer to laplacetransform 1+t is 1/s+1/(s^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 1+t

laplace transform

1 + t

\frac{1}{s} + \frac{1}{s ^{2}}

Solution steps

L {1 + t}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {1} + L {t}

L {1} : \frac{1}{s}

L {t} : \frac{1}{s ^{2}}

= \frac{1}{s} + \frac{1}{s ^{2}}

\frac{\partial}{\partial x} (3 x^{3} + y^{3} - 12 x y)

x \to - 2 lim (7 x + 4)

x \to 8 - lim (\frac{5}{( x - 8 ) ^{2}})

\frac{q x + r}{s x + t}

\int 4 x^{5} - 2 x^{3} + x - 2 d x

What is laplacetransform 1+t ?
The answer to laplacetransform 1+t is 1/s+1/(s^2)