What is the first derivative of 3x+16 ?

The first derivative of 3x+16 is 3

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derivative of 3x+16

\frac{d}{d x} (3 x + 16)

3

Solution steps

\frac{d}{d x} (3 x + 16)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (16)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (16) = 0

= 3 + 0

Simplify

= 3

\frac{d}{d x} (- csc (x) - cos (x))

\frac{d ^{2}}{d x ^{2}} (1 + x^{2})

f (x) = x + \frac{1}{x}, at x = 2

\frac{d}{d t} (\frac{3}{t})

h (x) = sin^{5} (x)