What is the integral of 1/(2sqrt(u)) ?

The integral of 1/(2sqrt(u)) is sqrt(u)+C

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integral of 1/(2sqrt(u))

\int \frac{1}{2 u} d u

u + C

Solution steps

\int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Apply the Power Rule

: 2 u^{\frac{1}{2}}

= \frac{1}{2} \cdot 2 u^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 u^{\frac{1}{2}} : u

= u

Add a constant to the solution

= u + C

f (x) = e x

\int ln (1 + x^{2}) d x

\int 4 e^{5 x} d x

\int (3 t - 5) e^{2 t} d t

cos (sin (15 e^{x}))

What is the integral of 1/(2sqrt(u)) ?
The integral of 1/(2sqrt(u)) is sqrt(u)+C