What is area 7x^4-7x^2,8x^2,0 ?

The answer to area 7x^4-7x^2,8x^2,0 is No Solution

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area 7x^4-7x^2,8x^2,0

area

7 x^{4} - 7 x^{2}, 8 x^{2}, 0

No Solution

Solution steps

To find the intersection points solve

f_{i} (x) = f_{j} (x)

7 x^{4} - 7 x^{2} = 8 x^{2} : x = \frac{15}{7}, x = - \frac{15}{7}, x = 0

7 x^{4} - 7 x^{2} = 0 : x = 1, x = - 1, x = 0

8 x^{2} = 0 : x = 0

Curves not bounded

= No Solution

\frac{\partial}{\partial y} (e^{- (x^{2} + y^{2})})

x \to 4 lim (\frac{( ln ( x ) - ln ( 4 ) )}{x - 4})

y^{^{'}} = x^{2} y^{2}

\int \frac{sin ^{2} ( x )}{cos ( x )} d x

\int \frac{2 s - 4}{( s ^{2} - 4 s + 20 ) ^{2}} d s

What is area 7x^4-7x^2,8x^2,0 ?
The answer to area 7x^4-7x^2,8x^2,0 is No Solution