What is the tangent of 5x^2+2x,\at x=3 ?

The tangent of 5x^2+2x,\at x=3 is y=32x-45

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tangent of 5x^2+2x,\at x=3

tangent of

5 x^{2} + 2 x, at x = 3

y = 32 x - 45

Solution steps

Find the tangent point:

(3, 51)

Find the slope of

y = 5 x^{2} + 2 x : \frac{d y}{d x} = 10 x + 2

Compute the slope of

y = 5 x^{2} + 2 x

x = 3 : m = 32

Find the line with slope m=

32

and passing through

(3, 51) : y = 32 x - 45

y = 32 x - 45

\int sin^{3} (4 θ) cos (4 θ) d θ

f (x) = x^{2} + 4

\frac{d y}{d x} = \frac{1 + x y}{1 + x}

\frac{\partial}{\partial y} (x sin (x y))

\frac{d}{d x} (sin (2 x - 1))

What is the tangent of 5x^2+2x,\at x=3 ?
The tangent of 5x^2+2x,\at x=3 is y=32x-45