What is the derivative of e^{2tsin(2t)} ?

The derivative of e^{2tsin(2t)} is e^{2tsin(2t)}*2(sin(2t)+2tcos(2t))

What is the first derivative of e^{2tsin(2t)} ?

The first derivative of e^{2tsin(2t)} is e^{2tsin(2t)}*2(sin(2t)+2tcos(2t))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

e^{2 t s i n (2 t)}

e^{2 t s i n (2 t)} \cdot 2 (sin (2 t) + 2 t cos (2 t))

Solution steps

\frac{d}{d t} (e^{2 t s i n (2 t)})

Apply the chain rule:

e^{2 t s i n (2 t)} \frac{d}{d t} (2 t sin (2 t))

= e^{2 t s i n (2 t)} \frac{d}{d t} (2 t sin (2 t))

\frac{d}{d t} (2 t sin (2 t)) = 2 (sin (2 t) + 2 t cos (2 t))

= e^{2 t s i n (2 t)} \cdot 2 (sin (2 t) + 2 t cos (2 t))

\int - a cos (x) d x

\frac{d}{d x} (arctan (x^{3} - 1))

\frac{\partial}{\partial x} (- 2 y e^{x^{2} - y^{2}})

e^{- 3 x + 1} + 8

\int \frac{e ^{2 t}}{e ^{2 t} - e ^{- 2 t}} d t

What is the derivative of e^{2tsin(2t)} ?
The derivative of e^{2tsin(2t)} is e^{2tsin(2t)}*2(sin(2t)+2tcos(2t))
What is the first derivative of e^{2tsin(2t)} ?
The first derivative of e^{2tsin(2t)} is e^{2tsin(2t)}*2(sin(2t)+2tcos(2t))