What is the tangent of f(x)=sqrt(4x+65),(4,9) ?

The tangent of f(x)=sqrt(4x+65),(4,9) is y= 2/9 x+73/9

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tangent of f(x)=sqrt(4x+65),(4,9)

tangent of

f (x) = 4 x + 65, (4, 9)

y = \frac{2}{9} x + \frac{73}{9}

Solution steps

Find the slope of

f (x) = 4 x + 65 : \frac{df ( x )}{d x} = \frac{2}{4 x + 65}

Compute the slope of

f (x) = 4 x + 65

(4, 9) : m = \frac{2}{9}

Find the line with slope m=

\frac{2}{9}

and passing through

(4, 9) : y = \frac{2}{9} x + \frac{73}{9}

y = \frac{2}{9} x + \frac{73}{9}

y = x, y = (x - 3), (3, 5.3)

\frac{\partial}{\partial y} (x^{\frac{1}{2}} y^{\frac{3}{2}})

\int_{0}^{y^{3}} x e^{- \frac{x}{y}} d x

\int \frac{24}{1 - cos ( 3 x )} d x

\int \frac{18}{1 - cos ( 9 x )} d x

What is the tangent of f(x)=sqrt(4x+65),(4,9) ?
The tangent of f(x)=sqrt(4x+65),(4,9) is y= 2/9 x+73/9