What is area x= 1/2 y^2,y=1,y=-1/2 x+3 ?

The answer to area x= 1/2 y^2,y=1,y=-1/2 x+3 is No Solution

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x= 1/2 y^2,y=1,y=-1/2 x+3

area

x = \frac{1}{2} y^{2}, y = 1, y = - \frac{1}{2} x + 3

No Solution

Solution steps

Isolate

y

for

x = \frac{1}{2} y^{2} : y = 2 x, y = - 2 x

f_{1} (x) = 2 x

f_{2} (x) = - 2 x

To find the intersection points solve

f_{i} (x) = f_{j} (x)

2 x = - 2 x : x = 0

2 x = 1 : x = \frac{1}{2}

2 x = - \frac{1}{2} x + 3 : x = 2

- 2 x = 1 :

No Solution for

x \in R

- 2 x = - \frac{1}{2} x + 3 : x = 18

1 = - \frac{1}{2} x + 3 : x = 4

Curves not bounded

= No Solution

\frac{\partial}{\partial y} (\frac{- y}{y ^{2} + x ^{2}})

\frac{d}{d x} (\frac{3 x - 1}{x ^{2} + 2})

\frac{d}{d x} (sin (8 cos (x)))

\int \frac{tan ^{3} ( θ )}{cos ^{4} ( θ )} d θ

x y^{^{''}} + y^{^{'}} = 0

What is area x= 1/2 y^2,y=1,y=-1/2 x+3 ?
The answer to area x= 1/2 y^2,y=1,y=-1/2 x+3 is No Solution