What is the tangent of 2x-2x^2 ?

The tangent of 2x-2x^2 is y=(2-4a_{0})x+2a_{0}^2

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tangent of 2x-2x^2

tangent of

2 x - 2 x^{2}

y = (2 - 4 a_{0}) x + 2 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 2 a_{0} - 2 a_{0}^{2})

Find the slope of

y = 2 x - 2 x^{2} : \frac{d y}{d x} = 2 - 4 x

Compute the slope of

y = 2 x - 2 x^{2}

x = a_{0} : m = 2 - 4 a_{0}

Find the line with slope m=

2 - 4 a_{0}

and passing through

(a_{0}, 2 a_{0} - 2 a_{0}^{2}) : y = (2 - 4 a_{0}) x + 2 a_{0}^{2}

y = (2 - 4 a_{0}) x + 2 a_{0}^{2}

0.9 x^{3} 3^{x}

\frac{\partial}{\partial x} (\frac{4 x}{3 y ^{2} + 1})

\frac{d}{d x} (3 x^{2} - 1 - x^{3})

\int e^{11 x} (11) d x

\int x^{3} tan (x y) d y

What is the tangent of 2x-2x^2 ?
The tangent of 2x-2x^2 is y=(2-4a_{0})x+2a_{0}^2