What is the derivative of arcsin(-4x) ?

The derivative of arcsin(-4x) is -4/(sqrt(1-16x^2))

What is the first derivative of arcsin(-4x) ?

The first derivative of arcsin(-4x) is -4/(sqrt(1-16x^2))

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\frac{d}{d x} (arcsin (- 4 x))

- \frac{4}{1 - 16 x ^{2}}

Solution steps

\frac{d}{d x} (arcsin (- 4 x))

Apply the chain rule:

\frac{1}{1 - ( - 4 x ) ^{2}} \frac{d}{d x} (- 4 x)

= \frac{1}{1 - ( - 4 x ) ^{2}} \frac{d}{d x} (- 4 x)

\frac{d}{d x} (- 4 x) = - 4

= \frac{1}{1 - ( - 4 x ) ^{2}} (- 4)

Simplify

\frac{1}{1 - ( - 4 x ) ^{2}} (- 4) : - \frac{4}{1 - 16 x ^{2}}

= - \frac{4}{1 - 16 x ^{2}}

n = 0 \sum \infty \frac{2}{3 ^{n + 1}}

y^{^{''}} - b^{2} y = 0

\int \frac{ln ( 2 ) x ^{5}}{x ^{2}} d x

\int_{0}^{4} x - (x - 2) d x

x^{^{''}} + x = 0, x (\frac{π}{2}) = 0, x^{^{'}} (\frac{π}{2}) = 1

What is the derivative of arcsin(-4x) ?
The derivative of arcsin(-4x) is -4/(sqrt(1-16x^2))
What is the first derivative of arcsin(-4x) ?
The first derivative of arcsin(-4x) is -4/(sqrt(1-16x^2))