What is the derivative of f(x)=(x+1)(3x^2-5x+2) ?

The derivative of f(x)=(x+1)(3x^2-5x+2) is 9x^2-4x-3

What is the first derivative of f(x)=(x+1)(3x^2-5x+2) ?

The first derivative of f(x)=(x+1)(3x^2-5x+2) is 9x^2-4x-3

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derivative of

f (x) = (x + 1) (3 x^{2} - 5 x + 2)

9 x^{2} - 4 x - 3

Solution steps

\frac{d}{d x} ((x + 1) (3 x^{2} - 5 x + 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 1, g = 3 x^{2} - 5 x + 2

= \frac{d}{d x} (x + 1) (3 x^{2} - 5 x + 2) + \frac{d}{d x} (3 x^{2} - 5 x + 2) (x + 1)

\frac{d}{d x} (x + 1) = 1

\frac{d}{d x} (3 x^{2} - 5 x + 2) = 6 x - 5

= 1 \cdot (3 x^{2} - 5 x + 2) + (6 x - 5) (x + 1)

Simplify

1 \cdot (3 x^{2} - 5 x + 2) + (6 x - 5) (x + 1) : 9 x^{2} - 4 x - 3

= 9 x^{2} - 4 x - 3

y^{^{''}} - y^{^{'}} - y = 0

x \to 4 lim (2 x - 1)

\frac{d}{d x} (2 e^{x} ln (x))

x \to - 2 lim (- x^{2} + 8 x - 4)

\int \frac{28}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of f(x)=(x+1)(3x^2-5x+2) ?
The derivative of f(x)=(x+1)(3x^2-5x+2) is 9x^2-4x-3
What is the first derivative of f(x)=(x+1)(3x^2-5x+2) ?
The first derivative of f(x)=(x+1)(3x^2-5x+2) is 9x^2-4x-3