What is the derivative of x^2+4x+5 ?

The derivative of x^2+4x+5 is 2x+4

What is the first derivative of x^2+4x+5 ?

The first derivative of x^2+4x+5 is 2x+4

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derivative of

x^{2} + 4 x + 5

2 x + 4

Solution steps

\frac{d}{d x} (x^{2} + 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x + 4 + 0

Simplify

= 2 x + 4

\frac{\partial}{\partial x} (x (y - 1))

\frac{d}{d x} (x^{2} lo g_{2} (x))

(x^{3} - 25 x)^{12} (- 5)

\frac{d}{d t} (\frac{( 2 t + 1 ) ^{\frac{3}{2}}}{3})

f (x) = (3 x + 1) (6 x - 2)

What is the derivative of x^2+4x+5 ?
The derivative of x^2+4x+5 is 2x+4
What is the first derivative of x^2+4x+5 ?
The first derivative of x^2+4x+5 is 2x+4