What is the derivative of x^2+x^4 ?

The derivative of x^2+x^4 is 2x+4x^3

What is the first derivative of x^2+x^4 ?

The first derivative of x^2+x^4 is 2x+4x^3

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\frac{d}{d x} (x^{2} + x^{4})

2 x + 4 x^{3}

Solution steps

\frac{d}{d x} (x^{2} + x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x^{4})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 2 x + 4 x^{3}

f (x) = \frac{1}{1 - x ^{2}}

\frac{d}{d x} (e^{2 x^{2} + 3})

f (x) = (1 - x) (x^{2} - 8)^{2}, at x = 3

f (x) = 7 arcsin (x^{4})

\int \frac{6 x + 7}{x ^{2} + 4 x + 4} d x

What is the derivative of x^2+x^4 ?
The derivative of x^2+x^4 is 2x+4x^3
What is the first derivative of x^2+x^4 ?
The first derivative of x^2+x^4 is 2x+4x^3