What is area f(x)=2x^2+3,x,[-1,2] ?

The answer to area f(x)=2x^2+3,x,[-1,2] is 27/2

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area f(x)=2x^2+3,x,[-1,2]

area

f (x) = 2 x^{2} + 3, x, [- 1, 2]

\frac{27}{2}

Decimal Notation

13.5

Solution steps

Apply the area formula:

\int_{- 1}^{2} 2 x^{2} + 3 - x d x

Solve

\int_{- 1}^{2} 2 x^{2} + 3 - x d x : \frac{27}{2}

The area is:

= \frac{27}{2}

x \to - 2 lim (x^{2} + x - 2)

f (x) = 2 x^{2} - x + 1, at x = 1

x y^{3} d x + (y + 1) e^{- x} d y = 0

f (x) = x^{2} + 2, at x = 2

- 5 x^{2}

What is area f(x)=2x^2+3,x,[-1,2] ?
The answer to area f(x)=2x^2+3,x,[-1,2] is 27/2